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save_tuple(): So long as the charter is rewriting for clarity, the snaky 

control flow had to be simplified.
This commit is contained in:
Tim Peters 2003-01-28 05:48:29 +00:00
parent ff57bff16e
commit d97da80dd5
1 changed files with 20 additions and 21 deletions
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41
Lib/pickle.py
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@ -458,27 +458,26 @@ class Pickler:
def save_tuple(self, object):
write = self.write
save = self.save
memo = self.memo
proto = self.proto
if proto >= 1:
n = len(object)
if n <= 3:
if not object:
write(EMPTY_TUPLE)
return
if proto >= 2:
for element in object:
save(element)
# Subtle. Same as in the big comment below.
if id(object) in memo:
get = self.get(memo[id(object)][0])
write(POP * n + get)
else:
write(_tuplesize2code[n])
self.memoize(object)
return
n = len(object)
if n == 0 and proto:
write(EMPTY_TUPLE)
return
save = self.save
memo = self.memo
if n <= 3 and proto >= 2:
for element in object:
save(element)
# Subtle. Same as in the big comment below.
if id(object) in memo:
get = self.get(memo[id(object)][0])
write(POP * n + get)
else:
write(_tuplesize2code[n])
self.memoize(object)
return
# proto 0, or proto 1 and tuple isn't empty, or proto > 1 and tuple
# has more than 3 elements.
@ -486,7 +485,7 @@ class Pickler:
for element in object:
save(element)
if object and id(object) in memo:
if n and id(object) in memo:
# Subtle. d was not in memo when we entered save_tuple(), so
# the process of saving the tuple's elements must have saved
# the tuple itself: the tuple is recursive. The proper action
@ -498,7 +497,7 @@ class Pickler:
if proto:
write(POP_MARK + get)
else: # proto 0 -- POP_MARK not available
write(POP * (len(object) + 1) + get)
write(POP * (n+1) + get)
return
# No recursion (including the empty-tuple case for protocol 0).