mirror of https://github.com/python/cpython
Beef-up docs and tests for itertools. Fix-up end-case for product().
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@ -89,6 +89,7 @@ loops that truncate the stream.
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.. versionadded:: 2.6
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.. versionadded:: 2.6
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.. function:: combinations(iterable, r)
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.. function:: combinations(iterable, r)
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Return successive *r* length combinations of elements in the *iterable*.
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Return successive *r* length combinations of elements in the *iterable*.
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@ -123,6 +124,17 @@ loops that truncate the stream.
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indices[j] = indices[j-1] + 1
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indices[j] = indices[j-1] + 1
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yield tuple(pool[i] for i in indices)
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yield tuple(pool[i] for i in indices)
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The code for :func:`combinations` can be also expressed as a subsequence
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of :func:`permutations` after filtering entries where the elements are not
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in sorted order (according to their position in the input pool)::
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def combinations(iterable, r):
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pool = tuple(iterable)
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n = len(pool)
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for indices in permutations(range(n), r):
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if sorted(indices) == list(indices):
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yield tuple(pool[i] for i in indices)
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.. versionadded:: 2.6
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.. versionadded:: 2.6
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.. function:: count([n])
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.. function:: count([n])
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@ -391,6 +403,18 @@ loops that truncate the stream.
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else:
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else:
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return
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return
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The code for :func:`permutations` can be also expressed as a subsequence of
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:func:`product`, filtered to exclude entries with repeated elements (those
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from the same position in the input pool)::
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def permutations(iterable, r=None):
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pool = tuple(iterable)
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n = len(pool)
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r = n if r is None else r
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for indices in product(range(n), repeat=r):
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if len(set(indices)) == r:
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yield tuple(pool[i] for i in indices)
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.. versionadded:: 2.6
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.. versionadded:: 2.6
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.. function:: product(*iterables[, repeat])
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.. function:: product(*iterables[, repeat])
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@ -401,9 +425,9 @@ loops that truncate the stream.
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``product(A, B)`` returns the same as ``((x,y) for x in A for y in B)``.
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``product(A, B)`` returns the same as ``((x,y) for x in A for y in B)``.
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The leftmost iterators are in the outermost for-loop, so the output tuples
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The leftmost iterators are in the outermost for-loop, so the output tuples
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cycle in a manner similar to an odometer (with the rightmost element
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cycle like an odometer (with the rightmost element changing on every
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changing on every iteration). This results in a lexicographic ordering
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iteration). This results in a lexicographic ordering so that if the
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so that if the inputs iterables are sorted, the product tuples are emitted
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inputs iterables are sorted, the product tuples are emitted
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in sorted order.
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in sorted order.
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To compute the product of an iterable with itself, specify the number of
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To compute the product of an iterable with itself, specify the number of
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@ -415,12 +439,11 @@ loops that truncate the stream.
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def product(*args, **kwds):
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def product(*args, **kwds):
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pools = map(tuple, args) * kwds.get('repeat', 1)
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pools = map(tuple, args) * kwds.get('repeat', 1)
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if pools:
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result = [[]]
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result = [[]]
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for pool in pools:
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for pool in pools:
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result = [x+[y] for x in result for y in pool]
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result = [x+[y] for x in result for y in pool]
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for prod in result:
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for prod in result:
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yield tuple(prod)
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yield tuple(prod)
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.. versionadded:: 2.6
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.. versionadded:: 2.6
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@ -40,9 +40,21 @@ def take(n, seq):
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'Convenience function for partially consuming a long of infinite iterable'
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'Convenience function for partially consuming a long of infinite iterable'
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return list(islice(seq, n))
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return list(islice(seq, n))
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def prod(iterable):
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return reduce(operator.mul, iterable, 1)
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def fact(n):
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def fact(n):
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'Factorial'
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'Factorial'
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return reduce(operator.mul, range(1, n+1), 1)
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return prod(range(1, n+1))
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def permutations(iterable, r=None):
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# XXX use this until real permutations code is added
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pool = tuple(iterable)
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n = len(pool)
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r = n if r is None else r
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for indices in product(range(n), repeat=r):
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if len(set(indices)) == r:
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yield tuple(pool[i] for i in indices)
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class TestBasicOps(unittest.TestCase):
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class TestBasicOps(unittest.TestCase):
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def test_chain(self):
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def test_chain(self):
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@ -62,11 +74,38 @@ class TestBasicOps(unittest.TestCase):
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def test_combinations(self):
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def test_combinations(self):
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self.assertRaises(TypeError, combinations, 'abc') # missing r argument
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self.assertRaises(TypeError, combinations, 'abc') # missing r argument
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self.assertRaises(TypeError, combinations, 'abc', 2, 1) # too many arguments
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self.assertRaises(TypeError, combinations, 'abc', 2, 1) # too many arguments
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self.assertRaises(TypeError, combinations, None) # pool is not iterable
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self.assertRaises(ValueError, combinations, 'abc', -2) # r is negative
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self.assertRaises(ValueError, combinations, 'abc', -2) # r is negative
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self.assertRaises(ValueError, combinations, 'abc', 32) # r is too big
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self.assertRaises(ValueError, combinations, 'abc', 32) # r is too big
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self.assertEqual(list(combinations(range(4), 3)),
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self.assertEqual(list(combinations(range(4), 3)),
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[(0,1,2), (0,1,3), (0,2,3), (1,2,3)])
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[(0,1,2), (0,1,3), (0,2,3), (1,2,3)])
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for n in range(8):
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def combinations1(iterable, r):
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'Pure python version shown in the docs'
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pool = tuple(iterable)
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n = len(pool)
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indices = range(r)
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yield tuple(pool[i] for i in indices)
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while 1:
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for i in reversed(range(r)):
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if indices[i] != i + n - r:
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break
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else:
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return
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indices[i] += 1
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for j in range(i+1, r):
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indices[j] = indices[j-1] + 1
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yield tuple(pool[i] for i in indices)
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def combinations2(iterable, r):
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'Pure python version shown in the docs'
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pool = tuple(iterable)
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n = len(pool)
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for indices in permutations(range(n), r):
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if sorted(indices) == list(indices):
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yield tuple(pool[i] for i in indices)
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for n in range(7):
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values = [5*x-12 for x in range(n)]
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values = [5*x-12 for x in range(n)]
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for r in range(n+1):
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for r in range(n+1):
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result = list(combinations(values, r))
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result = list(combinations(values, r))
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@ -78,6 +117,73 @@ class TestBasicOps(unittest.TestCase):
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self.assertEqual(len(set(c)), r) # no duplicate elements
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self.assertEqual(len(set(c)), r) # no duplicate elements
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self.assertEqual(list(c), sorted(c)) # keep original ordering
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self.assertEqual(list(c), sorted(c)) # keep original ordering
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self.assert_(all(e in values for e in c)) # elements taken from input iterable
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self.assert_(all(e in values for e in c)) # elements taken from input iterable
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self.assertEqual(result, list(combinations1(values, r))) # matches first pure python version
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self.assertEqual(result, list(combinations2(values, r))) # matches first pure python version
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# Test implementation detail: tuple re-use
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self.assertEqual(len(set(map(id, combinations('abcde', 3)))), 1)
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self.assertNotEqual(len(set(map(id, list(combinations('abcde', 3))))), 1)
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def test_permutations(self):
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self.assertRaises(TypeError, permutations) # too few arguments
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self.assertRaises(TypeError, permutations, 'abc', 2, 1) # too many arguments
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## self.assertRaises(TypeError, permutations, None) # pool is not iterable
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## self.assertRaises(ValueError, permutations, 'abc', -2) # r is negative
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## self.assertRaises(ValueError, permutations, 'abc', 32) # r is too big
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self.assertEqual(list(permutations(range(3), 2)),
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[(0,1), (0,2), (1,0), (1,2), (2,0), (2,1)])
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def permutations1(iterable, r=None):
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'Pure python version shown in the docs'
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pool = tuple(iterable)
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n = len(pool)
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r = n if r is None else r
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indices = range(n)
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cycles = range(n-r+1, n+1)[::-1]
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yield tuple(pool[i] for i in indices[:r])
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while n:
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for i in reversed(range(r)):
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cycles[i] -= 1
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if cycles[i] == 0:
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indices[i:] = indices[i+1:] + indices[i:i+1]
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cycles[i] = n - i
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else:
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j = cycles[i]
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indices[i], indices[-j] = indices[-j], indices[i]
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yield tuple(pool[i] for i in indices[:r])
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break
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else:
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return
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def permutations2(iterable, r=None):
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'Pure python version shown in the docs'
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pool = tuple(iterable)
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n = len(pool)
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r = n if r is None else r
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for indices in product(range(n), repeat=r):
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if len(set(indices)) == r:
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yield tuple(pool[i] for i in indices)
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for n in range(7):
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values = [5*x-12 for x in range(n)]
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for r in range(n+1):
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result = list(permutations(values, r))
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self.assertEqual(len(result), fact(n) / fact(n-r)) # right number of perms
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self.assertEqual(len(result), len(set(result))) # no repeats
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self.assertEqual(result, sorted(result)) # lexicographic order
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for p in result:
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self.assertEqual(len(p), r) # r-length permutations
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self.assertEqual(len(set(p)), r) # no duplicate elements
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self.assert_(all(e in values for e in p)) # elements taken from input iterable
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self.assertEqual(result, list(permutations1(values, r))) # matches first pure python version
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self.assertEqual(result, list(permutations2(values, r))) # matches first pure python version
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if r == n:
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self.assertEqual(result, list(permutations(values, None))) # test r as None
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self.assertEqual(result, list(permutations(values))) # test default r
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# Test implementation detail: tuple re-use
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## self.assertEqual(len(set(map(id, permutations('abcde', 3)))), 1)
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self.assertNotEqual(len(set(map(id, list(permutations('abcde', 3))))), 1)
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def test_count(self):
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def test_count(self):
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self.assertEqual(zip('abc',count()), [('a', 0), ('b', 1), ('c', 2)])
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self.assertEqual(zip('abc',count()), [('a', 0), ('b', 1), ('c', 2)])
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@ -288,7 +394,7 @@ class TestBasicOps(unittest.TestCase):
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def test_product(self):
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def test_product(self):
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for args, result in [
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for args, result in [
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([], []), # zero iterables ??? is this correct
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([], [()]), # zero iterables
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(['ab'], [('a',), ('b',)]), # one iterable
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(['ab'], [('a',), ('b',)]), # one iterable
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([range(2), range(3)], [(0,0), (0,1), (0,2), (1,0), (1,1), (1,2)]), # two iterables
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([range(2), range(3)], [(0,0), (0,1), (0,2), (1,0), (1,1), (1,2)]), # two iterables
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([range(0), range(2), range(3)], []), # first iterable with zero length
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([range(0), range(2), range(3)], []), # first iterable with zero length
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@ -305,10 +411,10 @@ class TestBasicOps(unittest.TestCase):
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set('abcdefg'), range(11), tuple(range(13))]
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set('abcdefg'), range(11), tuple(range(13))]
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for i in range(100):
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for i in range(100):
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args = [random.choice(argtypes) for j in range(random.randrange(5))]
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args = [random.choice(argtypes) for j in range(random.randrange(5))]
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n = reduce(operator.mul, map(len, args), 1) if args else 0
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expected_len = prod(map(len, args))
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self.assertEqual(len(list(product(*args))), n)
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self.assertEqual(len(list(product(*args))), expected_len)
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args = map(iter, args)
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args = map(iter, args)
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self.assertEqual(len(list(product(*args))), n)
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self.assertEqual(len(list(product(*args))), expected_len)
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# Test implementation detail: tuple re-use
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# Test implementation detail: tuple re-use
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self.assertEqual(len(set(map(id, product('abc', 'def')))), 1)
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self.assertEqual(len(set(map(id, product('abc', 'def')))), 1)
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@ -1885,10 +1885,7 @@ product_next(productobject *lz)
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if (result == NULL) {
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if (result == NULL) {
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/* On the first pass, return an initial tuple filled with the
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/* On the first pass, return an initial tuple filled with the
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first element from each pool. If any pool is empty, then
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first element from each pool. */
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whole product is empty and we're already done */
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if (npools == 0)
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goto empty;
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result = PyTuple_New(npools);
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result = PyTuple_New(npools);
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if (result == NULL)
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if (result == NULL)
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goto empty;
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goto empty;
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