mirror of https://github.com/python/cpython
Patch #1637: fix urlparse for URLs like 'http://x.com?arg=/foo'.
Fix by John Nagle.
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@ -316,6 +316,11 @@ class UrlParseTestCase(unittest.TestCase):
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self.assertEqual(type(p.hostname), type(uri))
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self.assertEqual(type(p.path), type(uri))
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def test_noslash(self):
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# Issue 1637: http://foo.com?query is legal
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self.assertEqual(urlparse.urlparse("http://example.com?blahblah=/foo"),
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('http', 'example.com', '', '', 'blahblah=/foo', ''))
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def test_main():
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test_support.run_unittest(UrlParseTestCase)
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@ -169,13 +169,12 @@ def _splitparams(url):
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return url[:i], url[i+1:]
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def _splitnetloc(url, start=0):
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for c in '/?#': # the order is important!
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delim = url.find(c, start)
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if delim >= 0:
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break
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else:
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delim = len(url)
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return url[start:delim], url[delim:]
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delim = len(url) # position of end of domain part of url, default is end
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for c in '/?#': # look for delimiters; the order is NOT important
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wdelim = url.find(c, start) # find first of this delim
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if wdelim >= 0: # if found
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delim = min(delim, wdelim) # use earliest delim position
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return url[start:delim], url[delim:] # return (domain, rest)
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def urlsplit(url, scheme='', allow_fragments=True):
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"""Parse a URL into 5 components:
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