allow the keyword else immediately after (no space) an integer (closes #21642)

This commit is contained in:
Benjamin Peterson 2014-06-07 12:36:39 -07:00
parent 024b2f52bf
commit c416162302
3 changed files with 24 additions and 5 deletions

View File

@ -80,6 +80,12 @@ class TokenTests(unittest.TestCase):
x = .3e14
x = 3.1e4
def test_float_exponent_tokenization(self):
# See issue 21642.
self.assertEqual(1 if 1else 0, 1)
self.assertEqual(1 if 0else 0, 0)
self.assertRaises(SyntaxError, eval, "0 if 1Else 0")
def test_string_literals(self):
x = ''; y = ""; self.assertTrue(len(x) == 0 and x == y)
x = '\''; y = "'"; self.assertTrue(len(x) == 1 and x == y and ord(x) == 39)

View File

@ -10,6 +10,10 @@ Release date: XXXX-XX-XX
Core and Builtins
-----------------
- Issue #21642: If the conditional if-else expression, allow an integer written
with no space between itself and the ``else`` keyword (e.g. ``True if 42else
False``) to be valid syntax.
- Issue #21523: Fix over-pessimistic computation of the stack effect of
some opcodes in the compiler. This also fixes a quadratic compilation
time issue noticeable when compiling code with a large number of "and"

View File

@ -1597,15 +1597,24 @@ tok_get(struct tok_state *tok, char **p_start, char **p_end)
} while (isdigit(c));
}
if (c == 'e' || c == 'E') {
exponent:
int e;
exponent:
e = c;
/* Exponent part */
c = tok_nextc(tok);
if (c == '+' || c == '-')
if (c == '+' || c == '-') {
c = tok_nextc(tok);
if (!isdigit(c)) {
tok->done = E_TOKEN;
if (!isdigit(c)) {
tok->done = E_TOKEN;
tok_backup(tok, c);
return ERRORTOKEN;
}
} else if (!isdigit(c)) {
tok_backup(tok, c);
return ERRORTOKEN;
tok_backup(tok, e);
*p_start = tok->start;
*p_end = tok->cur;
return NUMBER;
}
do {
c = tok_nextc(tok);