mirror of https://github.com/python/cpython
Clear out the regex cache when the TimeRE cache is invalidated by a locale
change. Fixes bug #1290505.
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@ -275,13 +275,14 @@ _regex_cache = {}
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def strptime(data_string, format="%a %b %d %H:%M:%S %Y"):
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"""Return a time struct based on the input string and the format string."""
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global _TimeRE_cache
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global _TimeRE_cache, _regex_cache
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_cache_lock.acquire()
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try:
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time_re = _TimeRE_cache
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locale_time = time_re.locale_time
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if _getlang() != locale_time.lang:
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_TimeRE_cache = TimeRE()
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_regex_cache = {}
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if len(_regex_cache) > _CACHE_MAX_SIZE:
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_regex_cache.clear()
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format_regex = _regex_cache.get(format)
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@ -462,10 +462,12 @@ class CacheTests(unittest.TestCase):
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# Make sure cache is recreated when current locale does not match what
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# cached object was created with.
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_strptime.strptime("10", "%d")
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_strptime.strptime("2005", "%Y")
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_strptime._TimeRE_cache.locale_time.lang = "Ni"
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original_time_re = id(_strptime._TimeRE_cache)
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_strptime.strptime("10", "%d")
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self.failIfEqual(original_time_re, id(_strptime._TimeRE_cache))
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self.failUnlessEqual(len(_strptime._regex_cache), 1)
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def test_regex_cleanup(self):
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# Make sure cached regexes are discarded when cache becomes "full".
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