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urlparse cleanup. rename keywords used as variables

This commit is contained in:
Senthil Kumaran 2012-06-29 11:07:27 -07:00
parent d07de40490
commit 97ac4a292e
1 changed files with 9 additions and 8 deletions
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15
Lib/urlparse.py
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@ -127,8 +127,8 @@ def urlparse(url, scheme='', allow_fragments=True):
Return a 6-tuple: (scheme, netloc, path, params, query, fragment).
Note that we don't break the components up in smaller bits
(e.g. netloc is a single string) and we don't expand % escapes."""
tuple = urlsplit(url, scheme, allow_fragments)
scheme, netloc, url, query, fragment = tuple
splitresult = urlsplit(url, scheme, allow_fragments)
scheme, netloc, url, query, fragment = splitresult
if scheme in uses_params and ';' in url:
url, params = _splitparams(url)
else:
@ -225,7 +225,8 @@ def urlunsplit(data):
empty query; the RFC states that these are equivalent)."""
scheme, netloc, url, query, fragment = data
if netloc or (scheme and scheme in uses_netloc and url[:2] != '//'):
if url and url[:1] != '/': url = '/' + url
if url and url[:1] != '/':
url = '/' + url
url = '//' + (netloc or '') + url
if scheme:
url = scheme + ':' + url
@ -344,13 +345,13 @@ def parse_qs(qs, keep_blank_values=0, strict_parsing=0):
If false (the default), errors are silently ignored.
If true, errors raise a ValueError exception.
"""
dict = {}
parsed_result = {}
for name, value in parse_qsl(qs, keep_blank_values, strict_parsing):
if name in dict:
dict[name].append(value)
parsed_result[name].append(value)
else:
dict[name] = [value]
return dict
parsed_result[name] = [value]
return parsed_result
def parse_qsl(qs, keep_blank_values=0, strict_parsing=0):
"""Parse a query given as a string argument.