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Patch #731514: Update recursion documentation to mention simple recursion.
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@ -896,15 +896,16 @@ The equivalent regular expression would be
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(\S+) - (\d+) errors, (\d+) warnings
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\end{verbatim}
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\leftline{\strong{Avoiding backtracking}}
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\leftline{\strong{Avoiding recursion}}
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If you create regular expressions that require the engine to perform a lot
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of backtracking, you may encounter a RuntimeError exception with the message
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\code{maximum recursion limit exceeded}. For example,
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If you create regular expressions that require the engine to perform a
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lot of recursion, you may encounter a RuntimeError exception with
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the message \code{maximum recursion limit} exceeded. For example,
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\begin{verbatim}
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>>> s = "<" + "that's a very big string!"*1000 + ">"
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>>> re.match('<.*?>', s)
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>>> import re
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>>> s = 'Begin ' + 1000*'a very long string ' + 'end'
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>>> re.match('Begin (\w| )*? end', s).end()
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Traceback (most recent call last):
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File "<stdin>", line 1, in ?
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File "/usr/local/lib/python2.3/sre.py", line 132, in match
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@ -912,8 +913,10 @@ Traceback (most recent call last):
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RuntimeError: maximum recursion limit exceeded
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\end{verbatim}
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You can often restructure your regular expression to avoid backtracking.
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The above regular expression can be recast as
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\regexp{\textless[\textasciicircum \textgreater]*\textgreater}. As a
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further benefit, such regular expressions will run faster than their
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backtracking equivalents.
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You can often restructure your regular expression to avoid recursion.
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\versionadded[Simple uses of the \regexp{*?} pattern are now
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special-cased to avoid recursion. Thus, the above regular expression
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can avoid recursion by being recast as \regexp{Begin [a-zA-Z0-9_ ]*?end}.
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As a further benefit, such regular expressions will run faster than
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their recursive equivalents.]{2.3}
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