mirror of https://github.com/python/cpython
bpo-29942: Fix the use of recursion in itertools.chain.from_iterable. (#889)
Fix the use of recursion in itertools.chain.from_iterable. Using recursion is unnecessary, and can easily cause stack overflows, especially when building in low optimization modes or with Py_DEBUG enabled.
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@ -1976,6 +1976,14 @@ class RegressionTests(unittest.TestCase):
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self.assertRaises(AssertionError, list, cycle(gen1()))
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self.assertEqual(hist, [0,1])
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def test_long_chain_of_empty_iterables(self):
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# Make sure itertools.chain doesn't run into recursion limits when
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# dealing with long chains of empty iterables. Even with a high
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# number this would probably only fail in Py_DEBUG mode.
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it = chain.from_iterable(() for unused in range(10000000))
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with self.assertRaises(StopIteration):
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next(it)
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class SubclassWithKwargsTest(unittest.TestCase):
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def test_keywords_in_subclass(self):
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# count is not subclassable...
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@ -301,6 +301,9 @@ Extension Modules
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Library
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-------
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- bpo-29942: Fix a crash in itertools.chain.from_iterable when encountering
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long runs of empty iterables.
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- bpo-10030: Sped up reading encrypted ZIP files by 2 times.
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- bpo-29204: Element.getiterator() and the html parameter of XMLParser() were
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@ -1864,9 +1864,10 @@ chain_next(chainobject *lz)
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{
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PyObject *item;
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if (lz->source == NULL)
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return NULL; /* already stopped */
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/* lz->source is the iterator of iterables. If it's NULL, we've already
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* consumed them all. lz->active is the current iterator. If it's NULL,
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* we should grab a new one from lz->source. */
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while (lz->source != NULL) {
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if (lz->active == NULL) {
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PyObject *iterable = PyIter_Next(lz->source);
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if (iterable == NULL) {
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@ -1889,8 +1890,11 @@ chain_next(chainobject *lz)
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else
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return NULL; /* input raised an exception */
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}
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/* lz->active is consumed, try with the next iterable. */
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Py_CLEAR(lz->active);
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return chain_next(lz); /* recurse and use next active */
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}
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/* Everything had been consumed already. */
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return NULL;
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}
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static PyObject *
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