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Bug #132313 error message confusing for assignment in lambda. 

They're actually complaining about something more specific, an assignment
in a lambda as an actual argument, so that Python parses the
lambda as if it were a keyword argument.  Like f(lambda x: x[0]=42).
The "lambda x: x[0]" part gets parsed as if it were a keyword, being
bound to 42, and the resulting error msg didn't make much sense.
This commit is contained in:
Tim Peters 2001-02-18 04:45:10 +00:00
parent 78349072f7
commit 4e30378e80
1 changed files with 8 additions and 1 deletions
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9
Python/compile.c
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@ -1522,8 +1522,15 @@ com_argument(struct compiling *c, node *n, PyObject **pkeywords)
m = CHILD(m, 0);
} while (NCH(m) == 1);
if (TYPE(m) != NAME) {
/* f(lambda x: x[0] = 3) ends up getting parsed with
* LHS test = lambda x: x[0], and RHS test = 3.
* SF bug 132313 points out that complaining about a keyword
* then is very confusing.
*/
com_error(c, PyExc_SyntaxError,
"keyword can't be an expression");
TYPE(m) == lambdef ?
"lambda cannot contain assignment" :
"keyword can't be an expression");
}
else {
PyObject *v = PyString_InternFromString(STR(m));