mirror of https://github.com/python/cpython
More robust way of choosing a non-existant uid (faster, too).
(Correct version -- the previous checkin was a keyboard slip.)
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@ -62,7 +62,7 @@ else:
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# Choose a non-existant uid.
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fakeuid = 4127
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while byuids.has_key(fakeuid):
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print 'fakeuid =', fakeuid
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fakeuid = (fakeuid * 3) % 0x10000
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try:
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pwd.getpwuid(fakeuid)
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