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gh-121657: Display correct error message for yield from outside of a function (GH-121680) 

Co-authored-by: blurb-it[bot] <43283697+blurb-it[bot]@users.noreply.github.com>
Co-authored-by: Bénédikt Tran <10796600+picnixz@users.noreply.github.com>
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Gregor 2024-07-13 17:14:39 +02:00 committed by GitHub
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commit 178e44de8f
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3 changed files with 8 additions and 1 deletions
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5
Lib/test/test_generators.py
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@ -2247,6 +2247,11 @@ Traceback (most recent call last):
...
SyntaxError: 'yield' outside function
>>> yield from [1,2]
Traceback (most recent call last):
...
SyntaxError: 'yield from' outside function
>>> def f(): x = yield = y
Traceback (most recent call last):
...

2
Misc/NEWS.d/next/Core and Builtins/2024-07-13-12-27-31.gh-issue-121657.wgOYLw.rst Normal file
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@ -0,0 +1,2 @@
Improve the :exc:`SyntaxError` message if the user tries to use
:keyword:`yield from <yield>` outside a function.

2
Python/compile.c
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@ -6119,7 +6119,7 @@ compiler_visit_expr(struct compiler *c, expr_ty e)
break;
case YieldFrom_kind:
if (!_PyST_IsFunctionLike(SYMTABLE_ENTRY(c))) {
return compiler_error(c, loc, "'yield' outside function");
return compiler_error(c, loc, "'yield from' outside function");
}
if (c->u->u_scope_type == COMPILER_SCOPE_ASYNC_FUNCTION) {
return compiler_error(c, loc, "'yield from' inside async function");