mirror of https://github.com/python/cpython
Sorting techniques edits (#124701)
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@ -47,11 +47,14 @@ lists. In contrast, the :func:`sorted` function accepts any iterable.
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Key Functions
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=============
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Both :meth:`list.sort` and :func:`sorted` have a *key* parameter to specify a
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function (or other callable) to be called on each list element prior to making
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The :meth:`list.sort` method and the functions :func:`sorted`,
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:func:`min`, :func:`max`, :func:`heapq.nsmallest`, and
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:func:`heapq.nlargest` have a *key* parameter to specify a function (or
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other callable) to be called on each list element prior to making
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comparisons.
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For example, here's a case-insensitive string comparison:
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For example, here's a case-insensitive string comparison using
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:meth:`str.casefold`:
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.. doctest::
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@ -272,6 +275,70 @@ to make it usable as a key function::
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sorted(words, key=cmp_to_key(strcoll)) # locale-aware sort order
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Strategies For Unorderable Types and Values
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===========================================
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A number of type and value issues can arise when sorting.
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Here are some strategies that can help:
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* Convert non-comparable input types to strings prior to sorting:
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.. doctest::
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>>> data = ['twelve', '11', 10]
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>>> sorted(map(str, data))
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['10', '11', 'twelve']
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This is needed because most cross-type comparisons raise a
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:exc:`TypeError`.
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* Remove special values prior to sorting:
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.. doctest::
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>>> from math import isnan
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>>> from itertools import filterfalse
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>>> data = [3.3, float('nan'), 1.1, 2.2]
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>>> sorted(filterfalse(isnan, data))
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[1.1, 2.2, 3.3]
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This is needed because the `IEEE-754 standard
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<https://en.wikipedia.org/wiki/IEEE_754>`_ specifies that, "Every NaN
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shall compare unordered with everything, including itself."
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Likewise, ``None`` can be stripped from datasets as well:
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.. doctest::
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>>> data = [3.3, None, 1.1, 2.2]
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>>> sorted(x for x in data if x is not None)
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[1.1, 2.2, 3.3]
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This is needed because ``None`` is not comparable to other types.
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* Convert mapping types into sorted item lists before sorting:
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.. doctest::
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>>> data = [{'a': 1}, {'b': 2}]
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>>> sorted(data, key=lambda d: sorted(d.items()))
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[{'a': 1}, {'b': 2}]
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This is needed because dict-to-dict comparisons raise a
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:exc:`TypeError`.
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* Convert set types into sorted lists before sorting:
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.. doctest::
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>>> data = [{'a', 'b', 'c'}, {'b', 'c', 'd'}]
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>>> sorted(map(sorted, data))
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[['a', 'b', 'c'], ['b', 'c', 'd']]
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This is needed because the elements contained in set types do not have a
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deterministic order. For example, ``list({'a', 'b'})`` may produce
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either ``['a', 'b']`` or ``['b', 'a']``.
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Odds and Ends
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=============
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