mirror of https://github.com/python/cpython
Restored commonprefix() semantics.
This commit is contained in:
parent
a48b526745
commit
03c06ee7fc
|
@ -89,29 +89,6 @@ def dirname(s): return split(s)[0]
|
|||
def basename(s): return split(s)[1]
|
||||
|
||||
|
||||
# Return the longest prefix of all list elements.
|
||||
# XXX completely untested on Mac!!!
|
||||
|
||||
def commonprefix(m):
|
||||
"Given a list of pathnames, returns the longest common leading component"
|
||||
if not m: return ''
|
||||
n = m[:]
|
||||
for i in range(len(n)):
|
||||
n[i] = n[i].split(os.sep)
|
||||
# if os.sep didn't have any effect, try os.altsep
|
||||
if os.altsep and len(n[i]) == 1:
|
||||
n[i] = n[i].split(os.altsep)
|
||||
|
||||
prefix = n[0]
|
||||
for item in n:
|
||||
for i in range(len(prefix)):
|
||||
if prefix[:i+1] <> item[:i+1]:
|
||||
prefix = prefix[:i]
|
||||
if i == 0: return ''
|
||||
break
|
||||
return os.sep.join(prefix)
|
||||
|
||||
|
||||
def isdir(s):
|
||||
"""Return true if the pathname refers to an existing directory."""
|
||||
|
||||
|
@ -166,6 +143,19 @@ def exists(s):
|
|||
return 0
|
||||
return 1
|
||||
|
||||
# Return the longest prefix of all list elements.
|
||||
|
||||
def commonprefix(m):
|
||||
"Given a list of pathnames, returns the longest common leading component"
|
||||
if not m: return ''
|
||||
prefix = m[0]
|
||||
for item in m:
|
||||
for i in range(len(prefix)):
|
||||
if prefix[:i+1] <> item[:i+1]:
|
||||
prefix = prefix[:i]
|
||||
if i == 0: return ''
|
||||
break
|
||||
return prefix
|
||||
|
||||
def expandvars(path):
|
||||
"""Dummy to retain interface-compatibility with other operating systems."""
|
||||
|
|
Loading…
Reference in New Issue