mirror of https://github.com/python/cpython
26 lines
513 B
Python
26 lines
513 B
Python
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resource_body = """
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char *buf;
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int len;
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Handle h;
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if (!PyArg_ParseTuple(_args, "s#", &buf, &len))
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return NULL;
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h = NewHandle(len);
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if ( h == NULL ) {
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PyErr_NoMemory();
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return NULL;
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}
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HLock(h);
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memcpy(*h, buf, len);
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HUnlock(h);
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return (PyObject *)ResObj_New(h);
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"""
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f = ManualGenerator("Resource", resource_body)
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f.docstring = lambda: """Convert a string to a resource object.
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The created resource object is actually just a handle.
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Apply AddResource() to write it to a resource file.
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"""
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functions.append(f)
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