2000-02-02 11:10:15 -04:00
|
|
|
"""Bisection algorithms."""
|
1992-09-02 17:43:20 -03:00
|
|
|
|
2000-12-28 22:06:45 -04:00
|
|
|
def insort_right(a, x, lo=0, hi=None):
|
|
|
|
"""Insert item x in list a, and keep it sorted assuming a is sorted.
|
|
|
|
|
|
|
|
If x is already in a, insert it to the right of the rightmost x.
|
|
|
|
|
|
|
|
Optional args lo (default 0) and hi (default len(a)) bound the
|
|
|
|
slice of a to be searched.
|
|
|
|
"""
|
|
|
|
|
2000-02-02 11:10:15 -04:00
|
|
|
if hi is None:
|
|
|
|
hi = len(a)
|
|
|
|
while lo < hi:
|
2001-09-04 16:14:14 -03:00
|
|
|
mid = (lo+hi)//2
|
2000-02-02 11:10:15 -04:00
|
|
|
if x < a[mid]: hi = mid
|
|
|
|
else: lo = mid+1
|
|
|
|
a.insert(lo, x)
|
1992-09-02 17:43:20 -03:00
|
|
|
|
2000-12-28 22:06:45 -04:00
|
|
|
insort = insort_right # backward compatibility
|
|
|
|
|
|
|
|
def bisect_right(a, x, lo=0, hi=None):
|
|
|
|
"""Return the index where to insert item x in list a, assuming a is sorted.
|
|
|
|
|
|
|
|
The return value i is such that all e in a[:i] have e <= x, and all e in
|
2007-04-02 21:01:09 -03:00
|
|
|
a[i:] have e > x. So if x already appears in the list, a.insert(x) will
|
|
|
|
insert just after the rightmost x already there.
|
2000-12-28 22:06:45 -04:00
|
|
|
|
|
|
|
Optional args lo (default 0) and hi (default len(a)) bound the
|
|
|
|
slice of a to be searched.
|
|
|
|
"""
|
1992-09-02 17:43:20 -03:00
|
|
|
|
2000-02-02 11:10:15 -04:00
|
|
|
if hi is None:
|
|
|
|
hi = len(a)
|
|
|
|
while lo < hi:
|
2001-09-04 16:14:14 -03:00
|
|
|
mid = (lo+hi)//2
|
2000-02-02 11:10:15 -04:00
|
|
|
if x < a[mid]: hi = mid
|
|
|
|
else: lo = mid+1
|
|
|
|
return lo
|
2000-12-28 22:06:45 -04:00
|
|
|
|
|
|
|
bisect = bisect_right # backward compatibility
|
|
|
|
|
|
|
|
def insort_left(a, x, lo=0, hi=None):
|
|
|
|
"""Insert item x in list a, and keep it sorted assuming a is sorted.
|
|
|
|
|
|
|
|
If x is already in a, insert it to the left of the leftmost x.
|
|
|
|
|
|
|
|
Optional args lo (default 0) and hi (default len(a)) bound the
|
|
|
|
slice of a to be searched.
|
|
|
|
"""
|
|
|
|
|
|
|
|
if hi is None:
|
|
|
|
hi = len(a)
|
|
|
|
while lo < hi:
|
2001-09-04 16:14:14 -03:00
|
|
|
mid = (lo+hi)//2
|
2000-12-28 22:06:45 -04:00
|
|
|
if a[mid] < x: lo = mid+1
|
|
|
|
else: hi = mid
|
|
|
|
a.insert(lo, x)
|
|
|
|
|
|
|
|
|
|
|
|
def bisect_left(a, x, lo=0, hi=None):
|
|
|
|
"""Return the index where to insert item x in list a, assuming a is sorted.
|
|
|
|
|
|
|
|
The return value i is such that all e in a[:i] have e < x, and all e in
|
2007-04-02 21:01:09 -03:00
|
|
|
a[i:] have e >= x. So if x already appears in the list, a.insert(x) will
|
|
|
|
insert just before the leftmost x already there.
|
2000-12-28 22:06:45 -04:00
|
|
|
|
|
|
|
Optional args lo (default 0) and hi (default len(a)) bound the
|
|
|
|
slice of a to be searched.
|
|
|
|
"""
|
|
|
|
|
|
|
|
if hi is None:
|
|
|
|
hi = len(a)
|
|
|
|
while lo < hi:
|
2001-09-04 16:14:14 -03:00
|
|
|
mid = (lo+hi)//2
|
2000-12-28 22:06:45 -04:00
|
|
|
if a[mid] < x: lo = mid+1
|
|
|
|
else: hi = mid
|
|
|
|
return lo
|
2004-01-05 06:13:35 -04:00
|
|
|
|
|
|
|
# Overwrite above definitions with a fast C implementation
|
|
|
|
try:
|
|
|
|
from _bisect import bisect_right, bisect_left, insort_left, insort_right, insort, bisect
|
|
|
|
except ImportError:
|
|
|
|
pass
|