import os from . import _common from ._common import as_file, files from contextlib import contextmanager, suppress from importlib.abc import ResourceLoader from io import BytesIO, TextIOWrapper from pathlib import Path from types import ModuleType from typing import ContextManager, Iterable, Union from typing import cast from typing.io import BinaryIO, TextIO __all__ = [ 'Package', 'Resource', 'as_file', 'contents', 'files', 'is_resource', 'open_binary', 'open_text', 'path', 'read_binary', 'read_text', ] Package = Union[str, ModuleType] Resource = Union[str, os.PathLike] def open_binary(package: Package, resource: Resource) -> BinaryIO: """Return a file-like object opened for binary reading of the resource.""" resource = _common.normalize_path(resource) package = _common.get_package(package) reader = _common.get_resource_reader(package) if reader is not None: return reader.open_resource(resource) absolute_package_path = os.path.abspath( package.__spec__.origin or 'non-existent file') package_path = os.path.dirname(absolute_package_path) full_path = os.path.join(package_path, resource) try: return open(full_path, mode='rb') except OSError: # Just assume the loader is a resource loader; all the relevant # importlib.machinery loaders are and an AttributeError for # get_data() will make it clear what is needed from the loader. loader = cast(ResourceLoader, package.__spec__.loader) data = None if hasattr(package.__spec__.loader, 'get_data'): with suppress(OSError): data = loader.get_data(full_path) if data is None: package_name = package.__spec__.name message = '{!r} resource not found in {!r}'.format( resource, package_name) raise FileNotFoundError(message) return BytesIO(data) def open_text(package: Package, resource: Resource, encoding: str = 'utf-8', errors: str = 'strict') -> TextIO: """Return a file-like object opened for text reading of the resource.""" return TextIOWrapper( open_binary(package, resource), encoding=encoding, errors=errors) def read_binary(package: Package, resource: Resource) -> bytes: """Return the binary contents of the resource.""" with open_binary(package, resource) as fp: return fp.read() def read_text(package: Package, resource: Resource, encoding: str = 'utf-8', errors: str = 'strict') -> str: """Return the decoded string of the resource. The decoding-related arguments have the same semantics as those of bytes.decode(). """ with open_text(package, resource, encoding, errors) as fp: return fp.read() def path( package: Package, resource: Resource, ) -> 'ContextManager[Path]': """A context manager providing a file path object to the resource. If the resource does not already exist on its own on the file system, a temporary file will be created. If the file was created, the file will be deleted upon exiting the context manager (no exception is raised if the file was deleted prior to the context manager exiting). """ reader = _common.get_resource_reader(_common.get_package(package)) return ( _path_from_reader(reader, resource) if reader else _common.as_file( _common.files(package).joinpath(_common.normalize_path(resource))) ) @contextmanager def _path_from_reader(reader, resource): norm_resource = _common.normalize_path(resource) with suppress(FileNotFoundError): yield Path(reader.resource_path(norm_resource)) return opener_reader = reader.open_resource(norm_resource) with _common._tempfile(opener_reader.read, suffix=norm_resource) as res: yield res def is_resource(package: Package, name: str) -> bool: """True if 'name' is a resource inside 'package'. Directories are *not* resources. """ package = _common.get_package(package) _common.normalize_path(name) reader = _common.get_resource_reader(package) if reader is not None: return reader.is_resource(name) package_contents = set(contents(package)) if name not in package_contents: return False return (_common.from_package(package) / name).is_file() def contents(package: Package) -> Iterable[str]: """Return an iterable of entries in 'package'. Note that not all entries are resources. Specifically, directories are not considered resources. Use `is_resource()` on each entry returned here to check if it is a resource or not. """ package = _common.get_package(package) reader = _common.get_resource_reader(package) if reader is not None: return reader.contents() # Is the package a namespace package? By definition, namespace packages # cannot have resources. namespace = ( package.__spec__.origin is None or package.__spec__.origin == 'namespace' ) if namespace or not package.__spec__.has_location: return () return list(item.name for item in _common.from_package(package).iterdir())