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:mod:`!codeop` --- Compile Python code
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======================================
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2007-08-15 11:28:22 -03:00
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.. module:: codeop
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:synopsis: Compile (possibly incomplete) Python code.
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2016-06-11 16:02:54 -03:00
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2007-08-15 11:28:22 -03:00
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.. sectionauthor:: Moshe Zadka <moshez@zadka.site.co.il>
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.. sectionauthor:: Michael Hudson <mwh@python.net>
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2016-06-11 16:02:54 -03:00
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**Source code:** :source:`Lib/codeop.py`
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--------------
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2007-08-15 11:28:22 -03:00
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The :mod:`codeop` module provides utilities upon which the Python
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read-eval-print loop can be emulated, as is done in the :mod:`code` module. As
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a result, you probably don't want to use the module directly; if you want to
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include such a loop in your program you probably want to use the :mod:`code`
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module instead.
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There are two parts to this job:
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2023-03-30 19:51:36 -03:00
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#. Being able to tell if a line of input completes a Python statement: in
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short, telling whether to print '``>>>``' or '``...``' next.
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#. Remembering which future statements the user has entered, so subsequent
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input can be compiled with these in effect.
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The :mod:`codeop` module provides a way of doing each of these things, and a way
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of doing them both.
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To do just the former:
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.. function:: compile_command(source, filename="<input>", symbol="single")
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Tries to compile *source*, which should be a string of Python code and return a
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code object if *source* is valid Python code. In that case, the filename
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attribute of the code object will be *filename*, which defaults to
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``'<input>'``. Returns ``None`` if *source* is *not* valid Python code, but is a
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prefix of valid Python code.
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If there is a problem with *source*, an exception will be raised.
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:exc:`SyntaxError` is raised if there is invalid Python syntax, and
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:exc:`OverflowError` or :exc:`ValueError` if there is an invalid literal.
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The *symbol* argument determines whether *source* is compiled as a statement
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(``'single'``, the default), as a sequence of :term:`statement` (``'exec'``) or
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as an :term:`expression` (``'eval'``). Any other value will
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cause :exc:`ValueError` to be raised.
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2009-04-27 13:20:50 -03:00
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.. note::
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2007-08-16 21:24:54 -03:00
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It is possible (but not likely) that the parser stops parsing with a
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successful outcome before reaching the end of the source; in this case,
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trailing symbols may be ignored instead of causing an error. For example,
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a backslash followed by two newlines may be followed by arbitrary garbage.
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This will be fixed once the API for the parser is better.
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.. class:: Compile()
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Instances of this class have :meth:`~object.__call__` methods identical in signature to
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the built-in function :func:`compile`, but with the difference that if the
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instance compiles program text containing a :mod:`__future__` statement, the
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instance 'remembers' and compiles all subsequent program texts with the
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statement in force.
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.. class:: CommandCompiler()
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Instances of this class have :meth:`~object.__call__` methods identical in signature to
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:func:`compile_command`; the difference is that if the instance compiles program
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text containing a :mod:`__future__` statement, the instance 'remembers' and
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compiles all subsequent program texts with the statement in force.
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