/// -*- tab-width: 4; Mode: C++; c-basic-offset: 4; indent-tabs-mode: nil -*- /* * polygon.cpp * Copyright (C) Andrew Tridgell 2011 * * This file is free software: you can redistribute it and/or modify it * under the terms of the GNU General Public License as published by the * Free Software Foundation, either version 3 of the License, or * (at your option) any later version. * * This file is distributed in the hope that it will be useful, but * WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. * See the GNU General Public License for more details. * * You should have received a copy of the GNU General Public License along * with this program. If not, see . */ #include "AP_Math.h" /* The point in polygon algorithm is based on: http://www.ecse.rpi.edu/Homepages/wrf/Research/Short_Notes/pnpoly.html */ /* Polygon_outside(): test for a point in a polygon Input: P = a point, V[] = vertex points of a polygon V[n+1] with V[n]=V[0] Return: true if P is outside the polygon This does not take account of the curvature of the earth, but we expect that to be very small over the distances involved in the fence boundary */ bool Polygon_outside(const Vector2l &P, const Vector2l *V, unsigned n) { unsigned i, j; bool outside = true; for (i = 0, j = n-1; i < n; j = i++) { if ((V[i].y > P.y) == (V[j].y > P.y)) { continue; } float dx1, dx2, dy1, dy2; // we convert the deltas to floating point numbers to // prevent integer overflow while maintaining maximum precision dx1 = P.x - V[i].x; dx2 = V[j].x - V[i].x; dy1 = P.y - V[i].y; dy2 = V[j].y - V[i].y; if ( dx1 < dx2 * dy1 / dy2 ) { outside = !outside; } } return outside; } /* check if a polygon is complete. We consider a polygon to be complete if we have at least 4 points, and the first point is the same as the last point. That is the minimum requirement for the Polygon_outside function to work */ bool Polygon_complete(const Vector2l *V, unsigned n) { return (n >= 4 && V[n-1].x == V[0].x && V[n-1].y == V[0].y); }